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The velocity of an electron in the second orbit of ten times ionised sodium atom (Z=11) is v. The velocity of electron in its fifth orbit is: |
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Answer» Solution :`v=Z/N. C/(137) alpha (Z)/(n)," for some Z"` `v alpha 1/n` `v_(2)/v_(2)= n_(1)/n_(2) RARR v_(2)=n_(1)/n_(2) v_(1)=2/5v` |
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