1.

The velocity of an electron in the second orbit of ten times ionised sodium atom (Z=11) is v. The velocity of electron in its fifth orbit is:

Answer»

v
`(22)/(5)v`
`5/2 v`
`2/5v`

Solution :`v=Z/N. C/(137) alpha (Z)/(n)," for some Z"`
`v alpha 1/n`
`v_(2)/v_(2)= n_(1)/n_(2) RARR v_(2)=n_(1)/n_(2) v_(1)=2/5v`


Discussion

No Comment Found

Related InterviewSolutions