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The velocity of an electron in the second orbit of sodium atom (atomic number `= 11`) is `v`. The veocity of an electron in its fifth orboit wil beA. `v`B. `(22)/(5)v`C. `(5)/(2)v`D. `(2)/(5)v` |
Answer» Correct Answer - D `v_(n) prop (1)/(h) rArr (v_(5))/(v_(2)) = (2)/(5) rArr v_(5) = (2)/(5) v_(2) = (2)/(5) v` |
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