1.

The velocity of electron v in the second orbit of hydrogen, then its velocity in the fifth orbit will be ......

Answer»

`(5)/(7)v`
`(7)/(5)v`
`(2)/(5)v`
`(5)/(2)v`

Solution :The velocity of electron in `N^(th)` orbit of H ATOM
`vecv_(n)=(Ze^(2))/(2in_(0)nh)`
But for H,Z=1 and `(e^(2))/(2in_(0)h)` constant
`:.v_(n)prop(1)/(n)`
`:.(v_(5))/(v_(2))=(2)/(5)`
`:.v_(5)=(2)/(5)v_(2)`
`:.v_(5)=(2)/(5)v""[:.v_(2)=v]`


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