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The velocity of image in a situation as shown in the figure is |
Answer» Solution : `vecV_0` Velocity of object `= (9 HATI+12 hatj)m//s ` ` vecV_m ` Velocity of mirror `= -2hati m//s` `m= (f)/(f-u) =(-20 )/( - 20 - (-30))=-2` For velocity COMPONENT parallel to optical axis ` (vecV_(I//m))_(।। )=-m^2 ( vecV_0 //m)_(।। )` ` (vecV_(I//m),=-(-2)^2 (9 hati-(-2hati)=-44 hatim//s` For velocity component perpedicular to optical axis ` ( vecV_(I//m))_(bot)=m( vecV_(O//m))_(bot)=(-2)12 hatj =-24 hatj m//s` ` :.vecV_(I//m) =`velocity of imagew.r.t mirror ` = ( vecV_(I//m))_(II)+( vecV_(I//m))_(bot) = (-44 i - 24 hatj)m//s` also`vecV_(I//m) = vecV_1 - vecV_mor ` `vecV_I= ( -44 hati - 24 hatj ) - 2 hati` `=( -44 hati - 26 hatj ) m//s` |
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