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The velocity of molecules of a gas at temperature 120 K is v. At what temperature will the velocity be 2v? |
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Answer» 120 K `((v_(2))/(v_(1)))^(2)=(T_(2))/(T_(1))implies((2v)/(v))^(2)=(T_(2))/(120)` `therefore T_(2)=120xx4impliesT_(2)=480K` |
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