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The velocity-time graph of a particle moving in a straight line is shown in figure. The mass of the particle is `2kg`. Work done by all the forces acting on the particle in time interval between `t=0` to `t=10s` is A. (a) `300J`B. (b) `-300J`C. (c) `400J`D. (d) `-400J` |
Answer» Correct Answer - A From work-energy theorem, `W=DeltaKE=K_f-K_i=1/2m(v_f^2-v_i^2)` `=1/2xx2[(-20)^2-(10)^2]=300J` |
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