The velocity versus time curve of a moving point is as given ahead: The maximum acceleration is :

The velocity versus time curve of a moving point is as given ahead: Th

1.	The velocity versus time curve of a moving point is as given ahead: The maximum acceleration is :
Answer» `1 m//s^(2)` `2 m//s^(2)` `3 m//s^(2)` `4 m//s^(2)` Solution :Maximum acceleration is in PORTION BC ACCLERATION =slope of v-t GRAPH `=(60-20)/(40-30)` `=4 m//s^(2)`

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The velocity versus time curve of a moving point is as given ahead: The maximum acceleration is :

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