The vertices of a `triangleOBC` are `O(0,0) , B(-3,-1), C(-1,-3)`. Find the equation of the line parallel to BC and intersecting the sides OB and OC and whose perpendicular distance from the origin is `1/2`.

The vertices of a `triangleOBC` are `O(0,0) , B(-3,-1), C(-1,-3)`. Fin

1.	The vertices of a `triangleOBC` are `O(0,0) , B(-3,-1), C(-1,-3)`. Find the equation of the line parallel to BC and intersecting the sides OB and OC and whose perpendicular distance from the origin is `1/2`.
Answer» Equation of line BC `y+1=(-3+1)/(-1+3)(x+3)` `y+1=-x-3` `y=-x-4` `y=-x+c-(1)` `y+x-c=0` `\|(-C)/sqrt2\|=1/2` `C/sqrt2=1/2` `C=1/sqrt2` `y=-x+1/sqrt2` `sqrt2y=-sqrt2x+1` `sqrt2x+sqrt2y=1`.

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The vertices of a `triangleOBC` are `O(0,0) , B(-3,-1), C(-1,-3)`. Find the equation of the line parallel to BC and intersecting the sides OB and OC and whose perpendicular distance from the origin is `1/2`.

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