The vibrations of a string of length 60 cm at both ends are represented by the equation. y =4 sin[(pix)/(15)] cos (96 pi t) where x and y are in cm and t is in sec. What is the maximum displacement Ilt x = 5 cm?

The vibrations of a string of length 60 cm at both ends are represente

1.	The vibrations of a string of length 60 cm at both ends are represented by the equation. y =4 sin[(pix)/(15)] cos (96 pi t) where x and y are in cm and t is in sec. What is the maximum displacement Ilt x = 5 cm?
Answer» Solution :For `x =5,y = 4 sin (5pi//15) COS (96PI t)` or `y = 2 sqrt3 cos (96 pi t)` So y will be MAXIMUM when `cos (96 pi t)= max =1, i.e,. (y_(max))_(x=5) =2 sqrt 3 cm`

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The vibrations of a string of length 60 cm at both ends are represented by the equation. y =4 sin[(pix)/(15)] cos (96 pi t) where x and y are in cm and t is in sec. What is the maximum displacement Ilt x = 5 cm?

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