1.

The vibrations of a string of length 60 cm fixed at both ends are represented by the equation. y=4 sin [(pi x)/(15)] cos(96 pi t) where x and y are in cm and t in sec. (a) What is the maximum displacement al r = 5 cm? (b) What are the nodes located along the string ? (c) What is the velocity of the particle at x=7.5 and t=0.25 s ? (d) Write down the equations of component waves whose superposition gives the above wave.

Answer»

maximum displacement of a particle at a POINT at x = t cm is 4 cm
third node is formed at 30 cm from ONE end of the string
the velocity of a particle at x = 7.5 cm and t = 0.25 s is ZERO
equations of the component waves whose superposition gives the above equation are`y_1 =- 2 sin ((pix)/(15) - 96 pi t) " and " y_2 = 2 sin ((pix)/(15) + 96 pi t)`

ANSWER :B::C::D


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