The view in the figure is form above a plane mirror suspended by a threadconnectedto the centre of the mirror at a point A. A scaleis located0.75m (the distanceform point A to point P) to the rightof the centre fo the mirror. Initially, the palneof the mirror is parallel to the sidefo the scale, and the angleof incidence of a light raywhich isdirectedat the centreof the mirroris 30^(@). A small torqueappleid to the threadcausesthe mirrorto turn11.5^(@) away formits initial positon. The reflectedray thenintersects the scaleat point Q. The distanceform point P to point Q on the scale is

The view in the figure is form above a plane mirror suspended by a thr

1.	The view in the figure is form above a plane mirror suspended by a threadconnectedto the centre of the mirror at a point A. A scaleis located0.75m (the distanceform point A to point P) to the rightof the centre fo the mirror. Initially, the palneof the mirror is parallel to the sidefo the scale, and the angleof incidence of a light raywhich isdirectedat the centreof the mirroris 30^(@). A small torqueappleid to the threadcausesthe mirrorto turn11.5^(@) away formits initial positon. The reflectedray thenintersects the scaleat point Q. The distanceform point P to point Q on the scale is
Answer» `1.00m` `0.56m` `1.02m` `0.86m` Solution : `tan (11.5+41.5)^(@)` `= tan 53^(@) = (PQ)/(0.75) RARR PQ = (4)/(3) XX 0.75 = 1M`

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