1.

The voltage across and the current through a load are expressed as follows:V(t)=−170sin(377t−π6)Vi(t)=8 cos(377t+π6)AThe average power in watts (round of to one decimal place) consumed by the load is588.9

Answer» The voltage across and the current through a load are expressed as follows:

V(t)=170sin(377tπ6)V

i(t)=8 cos(377t+π6)A

The average power in watts (round of to one decimal place) consumed by the load is
  1. 588.9


Discussion

No Comment Found

Related InterviewSolutions