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The voltage across and the current through a load are expressed as follows:V(t)=−170sin(377t−π6)Vi(t)=8 cos(377t+π6)AThe average power in watts (round of to one decimal place) consumed by the load is588.9 |
Answer» The voltage across and the current through a load are expressed as follows: V(t)=−170sin(377t−π6)V i(t)=8 cos(377t+π6)A The average power in watts (round of to one decimal place) consumed by the load is
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