1.

The voltage of an A.C. source varies with time according to the equation V = 100 sin 100pit cos100pit, where t is in second and V is in volt, then .......

Answer»

the peak voltage of the source is 100 V
the peak voltage of the source is 50 V
the peak voltage of the source is `100/sqrt2`V
the FREQUENCY of the source is 50 HZ.

Solution :V=100 sin 100 `pit` cos 100 `pit`
=50 (2 sin 100 `PI`t cos 100 `pit`)
=50 sin (200`pi`t) comparing this eqn. with
`V=V_m sin omegat`
`therefore V_m`=50 V, `omega=200pi` rad/s , f=100 Hz.


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