1.

The voltage of an AC source varies with time according to the equation `V=100sin 100pitcos100pit` where `t` is in seconds and `V` is in volts. ThenA. The peak voltage of the source is `100` voltsB. The peak voltage of the source is `50 `voltsC. The peak voltage of the source is `100sqrt(2)` voltsD. The frequency of the source is `50Hz`

Answer» Correct Answer - B
`V=50xx2 sin 100pit cos 100pit=50sin 200pit`
`implies V_(0)=50` volts and `v=10Hz`


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