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The voltage over a cycle varies as `V=V_(0)sin omega t` for `0 le t le (pi)/(omega)` `=-V_(0)sin omega t` for `(pi)/(omega)le t le (2pi)/(omega)` The average value of the voltage one cycle isA. `(V_(0))/(sqrt2)`B. `((2)/(pi))V_(0)`C. `((2)/(pi))V_(0)`D. ZERO

Answer» Correct Answer - B


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