1.

The volume of 0.0168 mol of O_(2) obtained by decomposition of KClO_(4) and collected by displacementof water is 428 mL at a presure of 754 mm Hg at 25^(@)C.The pressure of water vapour at 25^(@)C

Answer»

18 mm Hg
20 mm Hg
22 mm Hg
24 mm Hg

Solution :Pressure of DRY GAS `P=nRT//V`
`=(0.0168xx0.0821xx1000xx760xx298)/428=730mm`
Pressure of moist gas =754mm
HENCE pressure of water VAPOUR `=754-730=24mm`


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