1.

The volume of a block of a metal changes by `0.12%` when it is heated through `20^(@)C` . The coefficient of linear expansion of the metal isA. `4 xx 10^(-5)"^(@) C^(-1)`B. `2 xx 10^(-5)"^(@) C^(-1)`C. `0.5 xx 10^(-5)"^(@) C^(-1)`D. `4 xx 10^(-4)"^(@) C^(-1)`

Answer» Correct Answer - B
Here, `(DeltaV)/(V) = 0.12%, = (0.12)/(100)`
`DeltaT = 20 .^(@)C`
Now, `gamma = (DeltaV)/(VDeltaT) = (0.12)/(100 xx 20) = 6 xx 10^(-5) .^(@)C^(-1)`
`:. alpha = (gamma)/(3) = 2 xx 10^(-5) .^(@)C^(-1)`


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