1.

The volume of a colloidal particle, V_(c) as compared to the volume of a solute particle in a true solution, V_(s), could be

Answer»

`(V_(c))/(V_(s))~~1`
`(V_(c))/(V_(s))~~10^(23)`
`(V_(c))/(V_(s))~~10^(-3)`
`(V_(c))/(V_(s))~~10^(3)`

Solution :For TRUE solutions, the DIAMETER RANGE of the PARTICLES is `1Å` to `10Å` and for colloidal particles, it is `10Å` to `1000Å`
`therefore(V_(c))/(V_(s))=((4//3)pir_(c)^(3))/((4//3)pir_(s)^(3))=((r_(C))/(r_(s)))^(3)=((10)/(1))^(3)=10^(3)`


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