The volume of a cylinder is 49,896 cm3 and its curved surface area i

1.	The volume of a cylinder is 49,896 cm3 and its curved surface area is 4752 sq.cm. Then its radius is ……… cm.A) 12.3 B) 10 C) 21 D) 13.7
Answer» Correct option is: C) 21 Given that the volume of the cylinder is 49896 \(cm^3\). \(\therefore\) \(\pi r^2h\) = 49896....(1) And curved surface area of cylinder is 4752 \(cm^2\). \(\therefore\) \(2 \pi rh\) = 4752...(2) On dividing equation (1) by (2), we get = \(\frac {\pi r^2h}{2\pi rh} = \frac {49896}{4752}\) \(\Rightarrow\) \(\frac r2 = 10.5 = \frac {21}2\) \(\Rightarrow\) r = \( \frac {21}2 \times 2 = 21 \, cm\) Hence, the radius of the base of cylinder is 21 cm. Correct option is: C) 21

The volume of a cylinder is 49,896 cm3 and its curved surface area is 4752 sq.cm. Then its radius is ……… cm.A) 12.3 B) 10 C) 21 D) 13.7

Answer»

Correct option is: C) 21

Given that the volume of the cylinder is 49896 \(cm^3\).

\(\therefore\) \(\pi r^2h\) = 49896....(1)

And curved surface area of cylinder is 4752 \(cm^2\).

\(\therefore\) \(2 \pi rh\) = 4752...(2)

On dividing equation (1) by (2), we get

= \(\frac {\pi r^2h}{2\pi rh} = \frac {49896}{4752}\)

\(\Rightarrow\) \(\frac r2 = 10.5 = \frac {21}2\)

\(\Rightarrow\) r = \( \frac {21}2 \times 2 = 21 \, cm\)

Hence, the radius of the base of cylinder is 21 cm.

Correct option is: C) 21