1.

In an exhibition hall, there are 24 display boards each of length 1 m 50 cm and breadth 1 m. There is a 100 m long aluminium strip, which is used to frame these boards. How many boards will be framed using this strip? Find also the length of the aluminium strip required for the remaining boards.

Answer»

Length of display board = 1 m 50 cm = 1.50 m

Breadth of display board = 1 m

Perimeter of one display board

= 2(length + breadth) = 2(1.50 + 1) m

= 2(2.50) m = 5 m

∴ Perimeter of 24 display boards = (24 × 5) m = 120 m

Number of boards will be framed using the aluminium strip of 100 m long = 100/5 = 20

∴ The length of the aluminium strip required to frame the remaining boards

= 120 m – 100 m = 20 m



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