1.

What is the length of outer boundary of the park shown in figure? What will be the total cost of fencing it at the rate of Rs. 20 per metre ? There is a rectangular flower bed in the center of the park. Find the cost of manuring the flower bed at the rate of Rs. 50 per square metre.

Answer»

The length of outer boundary of the park = (200 + 300 + 80 + 300 + 200 + 260) m
= 1340 m

∴ Cost of fencing the park at the rate of Rs. 20 per metre = Rs. (20 × 1340) = Rs. 26800

Area of the flower bed = (100 × 80) m2 = 8000 m2

Now, the cost of manuring the flower bed at the rate of Rs. 50 per square metre

= Rs. (50 × 8000)

= Rs. 400000



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