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The volume of a gas is reduced adibatically to `(1//4)` of its volume at `27^(@)C`. if `gamma = 1.4` . The new temperature will beA. `350xx4^(0.4)K`B. `300xx4^(0.4)K`C. `150xx4^(0.4)K`D. None of these |
Answer» Correct Answer - B Isothermal process `PdV+VdP=0` `(dP)/(P)=-(dV)/(V), (K)=(dP)/(-((dV)/(V)))=(dP)/(((dP)/(P)))=P` |
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