The volume of an ideal gas is `V` at pressure `P`. On increasing the pressure by `DeltaP`, change in volume of gas is `DeltaV_(1)`, under isothermal conditions and `DeltaV_(2)` under adiabatic conditions. Which is more and why?

The volume of an ideal gas is `V` at pressure `P`. On increasing the p

1.	The volume of an ideal gas is `V` at pressure `P`. On increasing the pressure by `DeltaP`, change in volume of gas is `DeltaV_(1)`, under isothermal conditions and `DeltaV_(2)` under adiabatic conditions. Which is more and why?
Answer» Under isothermal conditions, `K_(i)=(DeltaP)/(DeltaV_(1)//V)=P`, and under adiabatic conditions, `K_(a)= (DeltaP)/(DeltaV_(2)//V)=gammaP` Dividing, we get, `gamma=(DeltaV_(1))/(DeltaV_(2))` As `gammagt1, :. DeltaV_(1)gtDeltaV_(2)`

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The volume of an ideal gas is `V` at pressure `P`. On increasing the pressure by `DeltaP`, change in volume of gas is `DeltaV_(1)`, under isothermal conditions and `DeltaV_(2)` under adiabatic conditions. Which is more and why?

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