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The volume of (N)/(10)NaOH require to neutralise 100 ml of (N)/(25) HCl is |
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Answer» 30 ml Milli EQUIVALENT of base=milli equivalent of acid `N_(1)V_(1)=N_(2)V_(2) implies(1)/(10) xxV_(1)=(1)/(25)xx100,V_(1)=40ml` |
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