1.

The volume of (N)/(10)NaOH require to neutralise 100 ml of (N)/(25) HCl is

Answer»

30 ml
100 ml
40 ml
25 ml

Solution :For complete neutralisation,
Milli EQUIVALENT of base=milli equivalent of acid
`N_(1)V_(1)=N_(2)V_(2) implies(1)/(10) xxV_(1)=(1)/(25)xx100,V_(1)=40ml`


Discussion

No Comment Found