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The volume of `(N)/(10)NaOH` require to neutralise 100 ml of `(N)/(25)` HCl isA. 30 mlB. 100 mlC. 40 mlD. 25 ml |
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Answer» Correct Answer - C For complete neutralisation, Milli equivalent of base=milli equivalent of acid `N_(1)V_(1)=N_(2)V_(2) implies(1)/(10) xxV_(1)=(1)/(25)xx100,V_(1)=40ml` |
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