1.

The volume of steam produced by `1g` of water at `100^(@)C` is `1650 cm^(3)`. Calculate the change in internal energy during the change of state. Given `J= 4.2xx10^(7) erg`. `cal.^(-1), d= 981 cm^(s-2)`. Latent heat of stream `= 540 cal. G^(-1)`

Answer» Here, mass of water `= 1g`
`:.` Initial volume of water, `V_(1)= 1cm^(3)`
Volume of stream, `V_(2)= 1650 cm^(3)`
change of internal energy, `dU=?`
As the state of water is changing,
`:. dQ=mL`
`= 1xx540 cals= 540xx4.2xx10^(7) ergs`
`22.68xx10^(9) ergs`
Taking `P= 1` atmosphere
`= 76xx13.6xx981 dyn e cm^(-2)`
`dW=P dV= P(V_(2)-V_(1))`
`76xx13.6xx981(1650-1)`
`=76xx13.6xx981xx1649 erg`
As `dQ=dU+dW`
`:. dU=dQ-dW`
`= 22.68xx10^(9)-1.67xx10^(9)`
`= 21.01xx10^(9) ergs`


Discussion

No Comment Found

Related InterviewSolutions