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The volume of thin brass vessel and the volume of a solid cube are both equal to 1 litre. What will be the change in the volumes of the vessel and the cube upon being heated to 25^(@) C ? (Given alpha for brass = 1.9 xx 10^(-5) ""^(@) C^(-1)) |
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Answer» Solution :`Delta V = V (3 alpha) Delta T` `= (10^(-3)) ( 3 xx 1.9 xx 10^(-5) ) (25) xx 10^(6) cm^(3)` `because` 1 litre = `10^(-3)m^(3)= 10^(3) cm^(3) = 1.425 cm^(2)` |
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