The volume of water needed to dissolve 1 mg of PbSO4(Ksp=1.44×10−8M – InterviewSolution

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1.	The volume of water needed to dissolve 1 mg of PbSO4(Ksp=1.44×10−8M2) at 25 ∘C is approximately:(molar mass of Pb=207 g/mol)
Answer» The volume of water needed to dissolve $1 mg$ of $P b S O_{4} (K_{s p} = 1.44 \times 10^{- 8} M^{2})$ at $25^{\circ} C$ is approximately: (molar mass of $P b = 207 g/mol$ )

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