1.

The volume of water to be added to 100 cm^(3) of 0.5N H_(2)SO_(4) to get decinormal concentration is

Answer»

`450 cm^(3)`
`100 cm^(3)`
`400 cm^(3)`
`500 cm^(3)`

Solution :`N_(1)V_(1) = N_(2)V_(2) , 100 cm^(3) xx 0.5N`
`=0.05 N xx V_(2) xx` GRAM equivalent of `H_(2)SO_(4)`
`(100 xx 0.5)/(0.05 xx2) = 500 cm^(3) = V_(2)`


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