1.

The volume of water to be added to 100cm^(3) of 0.5 N H_(2)SO_(4) to get decinormal concentration is

Answer»

`100CM^(3)`
`450CM^(3)`
`500cm^(3)`
`400cm^(3)`

SOLUTION :`N_(1)V_(1)=N_(2)V_(2)", i.e., "0.5xx100=0.1xxV_(2)or V_(2)=500cm^(3)`
`therefore" Water to be added to "100cm^(3)" solution"=500-100=400cm^(3).`


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