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The volume `(V)` of a manatomic gas varies with its temperature `(T)` , as shown in the graph. The ratio of work done by the gas, to the heat absorbed by it, when it undergoes a change from state `A` to `B` , is A. `2/7`B. `2/5`C. `1/3`D. `2/3` |
Answer» Correct Answer - B `V prop T` Isobaric process `W = PDeltaV = muR DeltaT` `Delta Q = mu C_(P)Delta T` For monoatomic gas `f = 3` `C_(P)=(f/2 R+R) = 5/3R` So, `(W)/(Delta Q) = (muRDeltaT)/(mu C_(P)Delta T) = 2/5`. |
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