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The wave described by y = 0.25 sin (10 pi x - 2 pi t )where x and y are in metres and t in seconds, is a wave travelling along the : |
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Answer» `+` ve x -direction with frequency `pi` HZ and wavelength `lambda` = 0.2 m. y = 0.25 sin `(2 pi t - 10 pi x)` We know that WAVE travelling along. + x -direction is y = r sin `(omega t - kx)` `therefore "" omega = 2pi and k = 10 pi `. `rArr "" (2pi)/(lambda) = 10 pi"" therefore lambda = 0.2 ` m Now `omega = 2pi ` f `2 pi = 2 pi f "" rArr f = 1 ` Hz. |
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