InterviewSolution
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InterviewSolution
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The wave described by `y = 0.25 "sin"(10 pi x - 2pit)` , where x and y are in metres and t in seconds , is a wave travelling along the:A. `+ ve` x direction with frequency 1 Hz and wavelength `lambda = 0.2 m`B. `–ve` x direction with amplitude 0.25 m and wavelength `lambda = 0.2 m`C. `– ve` x direction with frequency 1 HzD. `+ ve` x direction with frequency π Hz and wavelength `lambda= 0.2m` |
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Answer» Correct Answer - A Given `y=0.25 sin (10pix-2pit)` Comparing with equation of wave `y=A sin (kx-omegat)` `A=0.25, k=10pi, omega=2pi` `(2pi)/(lambda)=10pi" "2pif=2pi` `f=1Hz` `lambda=(1)/(5)=0.2m` When sign of coefficient of t and x are opposite it means `(dx)/(dt)=V gt 0` i.e., wave is propagating in the direction of growing x. |
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