1.

The wavelength of a microwave is 3.0 mm and it's electric field has an amplitdude of 4Vm^(1). Find the frequency of the wave

Answer»

SOLUTION :`lambda=3.0mm=3.0xx10^(-3)` m, AMPLITUDE of magnetic field `B_0=(E_0)/C=(4)/(3xx10^8)=1.33xx10^(-7)T`.


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