1.

The wavelength of de-Broglie wave associated with a matter particle is 2Å. The momentum of the particle is

Answer»

<P>`3.3xx10^(-24)kg" "ms^(-1)`
`13.2XX10^(-24)kg" "ms^(-1)`
`3xx10^(-24)kg" "ms^(-1)`
`13.2xx10^(24)kg" "ms^(-1)`.

Solution :`because LAMDA=(H)/(p)`, Hence `p=(h)/(lamda)=(6.6xx10^(-34))/(2xx10^(-10))=3.3xx10^(-24)kg" "ms^(-1)`.


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