1.

The wavelength of de - Broglie wave is `2 mu m` , then its momentum is `( h = 6.63 xx 10^(-34 J-s)`A. `3.315 xx 10^(-28) kg - m//s`B. `1.66 xx 10^(-28) kg - m//s`C. `4.97 xx 10^(-28) kg-m//s`D. `9.9 xx 10^(-28) kg - m//s`

Answer» Correct Answer - A
`lambda = (h)/(p) rArr p = (h)/(lambda) = (6.63 xx 10^(-34))/(2 xx 10^(-6))`
`= 3.31 xx 10^(-28) kg - m//sec`


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