1.

The wavelength of electron in ground state is 2.116Å, then its momentum will be ......

Answer»

<P>`313gcms^(-1)`
`313kgms^(-1)`
`3.13xx10^(-24)GCMS^(-1)`
`3.13xx10^(-24)KGMS^(-1)`

Solution :`lamda=(h)/(p)=(6.62xx10^(-34))/(2.116xx10^(-10))`
`=3.1285xx10^(-24)=3.13xx10^(-24)kgms^(-1)`


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