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The wavelength of K_(alpha) line of an X-ray spectrum of an element of atomic no. Z= 11 is alpha.. The wavelength of same line of element of atomic no. Z' is 4lamda, then Z' is : |
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Answer» 4 `V=^(2)(z-B)^(2)` `(v_(1))/(v_(2))=((z_(1)-b)^(2))/((z_(2)-b)^(2))` But `v=(c)/(lambda)` `(lambda_(2))/(lambda_(1))=((z_(1)-1)^(2))/((z_(2)-1)^(2))` `(4LAMBDA)/(lambda)=((11-1)^(2))/((z.-1)^(2))=4` Then `z=6` |
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