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The wavelength of k_(alpha) line of X-ray spectrum of an ekonsent of atomic number z = 11 in lambda. The wavelength of same time of element of atomic number is z' is 4lambda. z' is |
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Answer» 4 `v_(1)/v_(2)=((z_(1)-b)^(2))/((z_(2)-b)^(2))` For `K_(alpha), b=1` `v_(1)/v_(2)=((z_(1)-1)/(z_(2)-1))^(2) rArr lambda_(2)/lambda_(1) =((z_(1)-1)/(z_(2)-1))^(2)` `(4LAMBDA)/(lambda)=((11-1)^(2))/((z-1)^(2))` Then z=6 |
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