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The wavelength of `L_alpha` line in X-ray spectrum of `._76Pt` is 1.32Å. The wavelength of `L_alpha` line in X-ray spectrum of another unknown element is 4.17Å. If screening constant for `L_alpha` line is 7.4, then atomic number of the unknown element isA. 78B. 47C. 40D. 35 |
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Answer» Correct Answer - B `sqrt(v) =a(Z-b)=sqrt(C/(lambda)) =a(Z-b)rArr sqrt((lambda_(2))/(lambda_(1)))=(a(78-7.4))/(a(Z_(2)-7.4))` `Z_(2)=47` |
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