Saved Bookmarks
| 1. |
The wavelength of light from the spectral emission line of sodium is 589 nm. Find the kinetic energy at which a neutron, would have the same the Broglie wavelength. |
|
Answer» Solution :GIVEN `:` `lambda = 589 nm = 5.89 xx 10^(-7) m` The de Broglie wavelength `lambda - ( h )/( p )= ( h )/( sqrt( 2mE_(k))) ` `RARR lambda^(2) = ( h^(2))/(2mE_(k))` Kinetic energy `E_(k )=( h^(2))/( 2mlambda^(2))` For neutron `m = 1.67 xx 10^(-27) kg` `E_(k)= ((6.63 xx 10^(-34))^(2))/( 2 xx 1.67 xx 10^(-31)xx ( 5.89 xx 10^(-7))^(2))` `= 3.79 xx 10^(-28)J` |
|