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The wavelength of light from the spectral emission line of sodium is 589 nm. Find the kinetic energyat which a. an electron, and b. a neutron, would have the same de Broglie wavelength. |
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Answer» <P> Solution :a. DE Broglie WAVELENGTH, `lambda=(h)/(p) therefore p=(h)/(lambda)``K.E_("electron")=(p^(2))/(2m_(E ))=(h^(2))/(2m_(e )lambda^(2))` B. `K.E_("neutron")=(h^(2))/(2m_(n)lambda^(2))` |
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