1.

The wavelength of light observed on the earth , from a moving star is found to decrease by 0.05%.Relative to the earth the star is :

Answer»

Moving away with a velocity of `1.5 xx 10^(5) m/s`
Coming closer with a velocity of ` 1.5 xx 10^(4) m/s`
Moving away with a velocity of `1.5 xx 10^(4) m/s`
Coming closer with a velocity of `1.5 xx 10^(4) m/s`

Solution :`(Delta lambda)/(lambda) = (V)/(c) to (0.05)/(100) = (v)/(3 xx 10^(8)) RIGHTARROW v = 1.5 xx 10^(5) m/s`
(Since wavelength is decreasing, so star is coming closer)


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