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The wavelength of maximum emitted energy of a body at 700 K is `4.08 mu m`. If the temperature of the body is raised to 1400 K , the wavelength of maximum emitted energy will beA. `1.02 mum`B. `16.32mum`C. `8.16mum`D. `2.04mum` |
Answer» Correct Answer - D `lamda_(m_(1))T_(1)=lamda_(m_(2))T_(2)` `therefore lamda_(m_(2))=(lamda_(m_(1))T_(1))/(T_(2))=4.08xx(700)/(1400)=2.04`m |
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