1.

The wavelength of photoelectric threshold energy of a metal is 230 nm . Determine the K.E. of the photoelectron ejected from the surface by U.V. radiation emitted from the 2^(nd) longest wavelength transition ( downward ) of electron in Lymann series of atomic spectrum of hydrogen.( R = 1.09677 xx 10^(7) m^(-1) )

Answer»


ANSWER :`1.074 XX 10^(-18)J`


Discussion

No Comment Found