1.

The wavelength of photon needed to remove a proton from a nucleus which is bound to the nucleus with 1 MeV energy is nearly .

Answer»

1.2 nm
`1.2xx10^(-3)nm`
`1.2xx10^(-6)nm`
`1.2xx10^(1)nm`

Solution :If energy of photon `E_(P)` is equal to or greater than magnitude of binding energy of PROTON |E| then only photon can eject a proton out of nucleus.Hence ,
`E_(p)ge|E|`
`THEREFORE (E_(P))_(MIN)=|E|`
`therefore (hc)/(lambda)=|E|`
`therefore lambda=(hc)/(|E|)`
`=(6.625xx10^(-34)xx3xx10^(8))/(1xx10^(6)xx1.6xx10^(-19))`
`=1.242xx10^(-12)m`
`=1.242xx10^(-3)xx10^(-9)m`
`=1.242xx10^(-3)nm`


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