1.

The wavelength of the first line of Lyman series for hydrogen atom is equal to that ofthe second line of Balmer series for a hydrogen like ion. The atomic number Z of hydrogen like ion is .........

Answer»

3
4
1
2

Solution :For the first LINE of Lyman series for hydrogen ATOM
`(HC)/(lambda_(1))=Rhc((1)/(1^(2))-(1)/(2^(2)))`
For the second line of Balmer series for a hydrogen like ion
`(hc)/(lambda_(2))=Z^(2)Rhc((1)/(2^(2))-(1)/(4^(2)))`
according to question `lambda_(1)=lambda_(2)`
`rArr ((1)/(1)-(1)/(2))=Z^(2)((1)/(4)-(1)/(16))`
`:.Z=2`


Discussion

No Comment Found

Related InterviewSolutions