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The wavelength of the yellow doublet components of the resonance Na line caused by the transition 3p rarr 3S are equal to 589.00 and 589.56nm. Find the splitting of the 3P term in eV units. |
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Answer» Solution :The splitting of the `NA` LINES is due to the fine structure splitting of `3p` lines (The `3S` state in nearly single except for possible hyperfine effects). The splitting of the `3p` level then equals the energy difference `DELTAE=(2piħc)/(lambda_(1))-(2piħc)/(lambda_(2))=(2piħc(lambda_(2)-lambda_(1)))/(lambda_(1)lambda_(2))~~(3piħcDelta lambda)/(lambda^(2))` Here `Delta lambda`= WAVELENGTH difference & `lambda=` average wavelength. Substitution GIVES `DeltaE=2.0meV` |
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