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the wavelengths of two waves are 50 and 51 cm respectively. If the temperature of the room is 20^(@) C, then what will be the number of beats produced per second by these waves, when the speed of sound at 0^(@) C is 332 m/s ? |
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Answer» 14 `v_(0) = 332sqrt((293)/(273)) = 332 xx 1.036 = 344 ms^(-1)` `n_(1) = (344 xx 100)/(50) = 688` HZ. `n_(2) = (344 xx 100)/(51) = 674 ` Hz. `therefore` No. of beats /sec = 688 - 674 = 14. correct choice is (a) . |
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