1.

the wavelengths of two waves are 50 and 51 cm respectively. If the temperature of the room is 20^(@) C, then what will be the number of beats produced per second by these waves, when the speed of sound at 0^(@) C is 332 m/s ?

Answer»

14
10
24
none of these

Solution :`(v_(20))/(332) = sqrt((293)/(273))`
`v_(0) = 332sqrt((293)/(273)) = 332 xx 1.036 = 344 ms^(-1)`
`n_(1) = (344 xx 100)/(50) = 688` HZ.
`n_(2) = (344 xx 100)/(51) = 674 ` Hz.
`therefore` No. of beats /sec = 688 - 674 = 14.
correct choice is (a) .


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