1.

The weekly wages of 1000 workmen are normally distributed around a mean of#70 and a standard deviation of #5 estimate the number of workers whose weekly wages will beMore than#75Less than#63

Answer»

Given :  The weekly wages of 1000 workmen are NORMALLY distributed around a mean of 70 and a standard deviation of  5

To Find : estimate the NUMBER of workers whose weekly wages will be

More than 75

Less than 63

Solution:

Mean = 70

SD = 5

Z score = ( VALUE - Mean ) / SD

More than 75

=> z score = ( 75 -  70)/5  = 1

=> 84.13 % less than 75    Hence  15.87 %  more than 75

=> 1000 * 15.87 /100   = 158.7  = 159

159 workers whose weekly wages will be More than 75

Less than 63

=> z score = ( 63 -  70)/5  = -1.4

= 8.08 % less than 63    

=> 1000 * 8.08 /100   = 80.8  = 81

81  workers whose weekly wages will be Less than 63

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